set与重载<
set是有序容器，在定义容器的时候必须要指定 key 的比较函数。只不过这个函数通常是默认的 less，表示小于关系，不用特意写出来：
template<
class Key, // 模板参数是key类型，即元素类型
class Compare = std::less
> class set; // 集合
C++ 里的 int、string 等基本类型都支持比较排序，放进有序容器里毫无问题。但很多自定义类型没有默认的比较函数，要作为容器的 key 就有点麻烦。虽然这种情况不多见，但有的时候还真是个“刚性需求”。解决这个问题一般是重载“<”，比如说我们有一个 Point 类，它是没有大小概念的，但只要给它重载“<”操作符，就可以放进有序容器里了：
/*************************************************************************
> File Name: 03-set.cpp
> Author:
> Mail:
> Created Time: Mon 25 Sep 2023 05:04:02 PM CST
************************************************************************/
#include
#include
using namespace std;
class Point
{
public:
Point(double x, double y) : m_x(x), m_y(y) {}
~Point() {}
bool operator < (const Point& rhs)
{
return m_x > rhs.m_x;
}
private:
double m_x, m_y;
};
int main()
{
set
s.emplace(Point(1.1, 2.2));
s.emplace(Point(2.2, 3.3));
return 0;
}
由于我是一个新手C++使用者，上述代码尽管重载了小于(<)运算符，但是编译报错：
ydqun@ydqhost chapter12 % g++ 03-set.cpp [0]
In file included from /usr/include/c++/9/bits/stl_tree.h:65,
from /usr/include/c++/9/set:60,
from 03-set.cpp:7:
/usr/include/c++/9/bits/stl_function.h: In instantiation of ‘constexpr bool std::less<_Tp>::operator()(const _Tp&, const _Tp&) const [with _Tp = Point]’:
/usr/include/c++/9/bits/stl_tree.h:2095:11: required from ‘std::pair
y = Point; _Val = Point; _KeyOfValue = std::_Identity
/usr/include/c++/9/bits/stl_tree.h:2413:19: required from ‘std::pair
_Val = Point; _KeyOfValue = std::_Identity
/usr/include/c++/9/bits/stl_set.h:463:64: required from ‘std::pair
_Key, _Compare, _Alloc>::emplace(_Args&& ...) [with _Args = {Point}; _Key = Point; _Compare = std::less
alloc_traits<_Alloc>::rebind<_Key>::other>::const_iterator = std::_Rb_tree_const_iterator
03-set.cpp:28:30: required from here
/usr/include/c++/9/bits/stl_function.h:386:20: error: no match for ‘operator<’ (operand types are ‘const Point’ and ‘const Point’)
386 | { return __x < __y; }
| ~~~~^~~~~
03-set.cpp:16:10: note: candidate: ‘bool Point::operator<(const Point&)’
16 | bool operator < (const Point& rhs)
| ^~~~~~~~
03-set.cpp:16:10: note: passing ‘const Point*’ as ‘this’ argument discards qualifiers
In file included from /usr/include/c++/9/bits/stl_algobase.h:64,
from /usr/include/c++/9/bits/stl_tree.h:63,
from /usr/include/c++/9/set:60,
from 03-set.cpp:7:
/usr/include/c++/9/bits/stl_pair.h:454:5: note: candidate: ‘template
454 | operator<(const pair<_T1, _T2>& __x, const pair<_T1, _T2>& __y)
| ^~~~~~~~
/usr/include/c++/9/bits/stl_pair.h:454:5: note: template argument deduction/substitution failed:
In file included from /usr/include/c++/9/bits/stl_tree.h:65,
from /usr/include/c++/9/set:60,
from 03-set.cpp:7:
/usr/include/c++/9/bits/stl_function.h:386:20: note: ‘const Point’ is not derived from ‘const std::pair<_T1, _T2>’
386 | { return __x < __y; }
| ~~~~^~~~~
In file included from /usr/include/c++/9/bits/stl_algobase.h:67,
from /usr/include/c++/9/bits/stl_tree.h:63,
from /usr/include/c++/9/set:60,
from 03-set.cpp:7:
/usr/include/c++/9/bits/stl_iterator.h:331:5: note: candidate: ‘template
...... 中间省略若几十行(无力吐槽C++编译出错提示)
/usr/include/c++/9/bits/stl_function.h:386:20: note: ‘const Point’ is not derived from ‘const std::__cxx11::basic_string<_CharT, _Traits, _Alloc>’
386 | { return __x < __y; }
| ~~~~^~~~~
In file included from /usr/include/c++/9/string:55,
from /usr/include/c++/9/bits/locale_classes.h:40,
from /usr/include/c++/9/bits/ios_base.h:41,
from /usr/include/c++/9/ios:42,
from /usr/include/c++/9/ostream:38,
from /usr/include/c++/9/iostream:39,
from 03-set.cpp:8:
/usr/include/c++/9/bits/basic_string.h:6239:5: note: candidate: ‘template
6239 | operator<(const basic_string<_CharT, _Traits, _Alloc>& __lhs,
| ^~~~~~~~
/usr/include/c++/9/bits/basic_string.h:6239:5: note: template argument deduction/substitution failed:
In file included from /usr/include/c++/9/bits/stl_tree.h:65,
from /usr/include/c++/9/set:60,
from 03-set.cpp:7:
/usr/include/c++/9/bits/stl_function.h:386:20: note: ‘const Point’ is not derived from ‘const std::__cxx11::basic_string<_CharT, _Traits, _Alloc>’
386 | { return __x < __y; }
| ~~~~^~~~~
In file included from /usr/include/c++/9/string:55,
from /usr/include/c++/9/bits/locale_classes.h:40,
from /usr/include/c++/9/bits/ios_base.h:41,
from /usr/include/c++/9/ios:42,
from /usr/include/c++/9/ostream:38,
from /usr/include/c++/9/iostream:39,
from 03-set.cpp:8:
/usr/include/c++/9/bits/basic_string.h:6251:5: note: candidate: ‘template
6251 | operator<(const _CharT* __lhs,
| ^~~~~~~~
/usr/include/c++/9/bits/basic_string.h:6251:5: note: template argument deduction/substitution failed:
In file included from /usr/include/c++/9/bits/stl_tree.h:65,
from /usr/include/c++/9/set:60,
from 03-set.cpp:7:
/usr/include/c++/9/bits/stl_function.h:386:20: note: mismatched types ‘const _CharT*’ and ‘Point’
386 | { return __x < __y; }
| ~~~~^~~~~
In file included from /usr/include/c++/9/bits/ios_base.h:46,
from /usr/include/c++/9/ios:42,
from /usr/include/c++/9/ostream:38,
from /usr/include/c++/9/iostream:39,
from 03-set.cpp:8:
/usr/include/c++/9/system_error:208:3: note: candidate: ‘bool std::operator<(const std::error_code&, const std::error_code&)’
208 | operator<(const error_code& __lhs, const error_code& __rhs) noexcept
| ^~~~~~~~
/usr/include/c++/9/system_error:208:31: note: no known conversion for argument 1 from ‘const Point’ to ‘const std::error_code&’
208 | operator<(const error_code& __lhs, const error_code& __rhs) noexcept
| ~~~~~~~~~~~~~~~~~~^~~~~
/usr/include/c++/9/system_error:282:3: note: candidate: ‘bool std::operator<(const std::error_condition&, const std::error_condition&)’
282 | operator<(const error_condition& __lhs,
| ^~~~~~~~
/usr/include/c++/9/system_error:282:36: note: no known conversion for argument 1 from ‘const Point’ to ‘const std::error_condition&’
282 | operator<(const error_condition& __lhs,
| ~~~~~~~~~~~~~~~~~~~~~~~^~~~~
相信不少新入坑C++的同学看到这类报错后头都大了（我也是）。
经过我长达半个小时的排查，终于从出错提示中找到答案，在报错信息中的第四行，如下：
/usr/include/c++/9/bits/stl_function.h: In instantiation of ‘constexpr bool std::less<_Tp>::operator()(const _Tp&, const _Tp&) const [with _Tp = Point]’:
这时候，我们可以知道是因为在类内重载<运算符时，少了const修饰，导致函数签名不匹配，我们只需要对重载的operator<()函数后面加上const修饰，即可解决，完整代码如下：
/*************************************************************************
> File Name: 03-set.cpp
> Author:
> Mail:
> Created Time: Mon 25 Sep 2023 05:04:02 PM CST
************************************************************************/
#include
#include
using namespace std;
class Point
{
public:
Point(double x, double y) : m_x(x), m_y(y) {}
~Point() {}
bool operator < (const Point& rhs) const
{
return m_x > rhs.m_x;
}
private:
double m_x, m_y;
};
int main()
{
set
s.emplace(Point(1.1, 2.2));
s.emplace(Point(2.2, 3.3));
return 0;
}